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$8 ($10 passline - $2 C&E). If the 2, 3
or 12 should roll, you’ll lose $4 (+$7 craps - $1 eleven - $10 passline)
instead of $10.
This time, though, in 36 decisions,
you’ve invested $72 (2 x $36) in hedge bets. The 2 and 12 will have each
rolled once, and the three and eleven twice. You would make $7 on the 2
($1 x 7), $14 on the 3 ($2 x 7), $7 on the 12 ($1 x 7), and $30 on the
eleven ($2 x 15). This totals $58 ($7 + $14 + $7 + $30), but you’ve
already invested $72 so you have a $14 ($72-$58) loss! Another winner for
the house!
Finally, you can make a 3-way craps bet (on
the 2, 3, and 12) for $3. This is different from the any craps bet because
the odds are higher - 30 to 1 for the 2 and 12, and 15 to 1 for the three.
So if the 2 or 12 roll you win $18 ($30 - $10 - $2) instead of losing $10,
and if the three rolls, you win $3 ($15 - $10 - $2) instead of losing $10.
This bet also means that you will win on the 7 and 11 (from your pass line
bet) and on the 2, 3, and 12 (from the 3-way craps bet). In 36 rolls,
however, this time you’ve invested $108 ($3 x 36). The 2 and 12 will
roll once, and the 3 twice. At 30 to 1, the 2 and 12 pay $30 each, for a
total of $60. At 15 to 1, the 3 pays $30 ($2 x 15). You made $90 ($30 +
$60) but spent $108 for a loss of $18!
Unfortunately, as you can see, you can
not profitably protect a $10 pass line bet by hedging it with craps bets.
Some craps writers have maintained that a craps hedge bet is only
profitable with a passline bet of $25 or more, with a $4 any craps bet.
Let’s look at the math. If you bet $4 any craps you’ll win $112, which
comes from $4 (bet) x 4 (number of times 2, 3, or 12 rolls) x 7 (payoff).
You’ll lose $144 ($4 x 36) ... » read more |
